find the valency of sodium and oxygen .(atomic number of sodium-11,atomic number of oxygen-8)
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Valency of Sodium is 1
Valency of Oxygen is 8-6= 2
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Given details:
Atomic number of Sodium (Na) = 11
Atomic number of Oxygen (O) = 8
Solution:
Valency is the number of electrons in the outermost shell of the atom, that can be lose or gained in order to make the atom a stable one.
Configuration of Sodium (Na) is 1s2 2s2 2p6 3s1
So, there is one electron in the outer most shell.
If it loses one electron, it can become a stable one. (i.e.) 8 electrons in outer shell.
So, valency of Sodium is +1.
Configuration of Oxygen (O) is 1s2 2s2 2p4
So, there are 6 electrons in the outer most shell.
If it gains 2 electrons , it can become a stable one. (i.e.) 8 electrons in outer shell.
So, valency of Oxygen is -2.
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