find the valeu of 'K' for which the
points we cellines a(7,-2) b (5,1) c(3,K) find the answar
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Answered by
0
Answer:
4
Step-by-step explanation:
Since points are collinear,
so, x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)=0
Take (7,−2) as (x
1
,y
1
), (5,1) as (x
2
,y
2
) and (3,k) as (x
3
,y
3
), we have
7(1−k)+5(k+2)+3(−2−1)=0
⇒ 7−7k+5k+10−9=0
⇒ 2k=8
⇒ k=4
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