Math, asked by shah14, 1 year ago

find the valie of p (-2/3) for p (y)=2y^3-y^2-13y-6

Answers

Answered by rijitasingh
11
is it right?????????
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Answered by mysticd
15
Hi ,

p( y ) = 2y³ - y² - 13y - 6

Value p (-2/3 )

= 2(-2/3 )³ - ( - 2/3 )² - 13(-2/3 ) - 6

= - 16/27 - 4/9 + 26/3 - 6

= ( -16 - 12 + 234 - 162 ) / 27

= ( 234 - 190 ) 27

= 44/27

I hope this helps you.

:)

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