Question

Find the valu of a if 6/3√2-2√3=3√2-a√3

Answer 1

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } = 3 \sqrt{2} - a \sqrt{3} \\ \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3}} = 3 \sqrt{2} - a \sqrt{3} \\ \frac{18 \sqrt{2} + 12 \sqrt{3} }{(3 \sqrt{2})^{2} - (2 \sqrt{3}) ^{2} } = 3 \sqrt{2} - a \sqrt{3} \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3}) }{18 - 12} = 3 \sqrt{2} - a \sqrt{3} \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3}) }{6} = 3 \sqrt{2} - a \sqrt{3} \\ 3 \sqrt{2 } + 2 \sqrt{3} =3 \sqrt{2} - a \sqrt{3} \\ so \: \: \: \: \: a = - 2$

Answer 2

Hey! Your Answer Is In Image..