find the valu of discriminate 2y2-y+2=0
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Answered by
4
Answer:
2y^2 - y + 2 = 0
Here,
a = 2
b = - 1
y = 2
We know,Discriminant = b^2 - 4ac
= (-1)^2 - 4(2)(2)
= 1 - 16
= -15
Answered by
6
EXPLANATION.
Quadratic equation.
⇒ 2y² - y + 2 = 0.
As we know that,
⇒ D = Discriminant or b² - 4ac.
⇒ D = (-1)² - 4(2)(2).
⇒ D = 1 - 16.
⇒ D = -15.
MORE INFORMATION.
Nature of the factor of the quadratic expression.
(1) = Real and different, if b² - 4ac > 0.
(2) = Rational and different, if b² - 4ac is a perfect square.
(3) = Real and equal, if b² - 4ac = 0.
(4) = If D < 0 Roots are imaginary and unequal or complex conjugate.
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