Math, asked by mahima9233, 3 months ago



Find the valu of k for which (×-1)

is a factor of (2×^3 + 9 ×^2+×+k)

Answers

Answered by khushiii7
0

Answer:

2(1)³+9(1)²+1+k=0

2+9+1+k=0

12+k=0

k=-12

Answered by bumithrabobbari
0

Answer:

k=-12

Step-by-step explanation:

f(x)=(2×^3 + 9 ×^2+×+k)

if (×-1)is a factor,then making x=1would make(×-1) equal to 0,and everything else in the equation multiply by that 0, resulting to

f(1)=0.

f(1)=2.1³+9.1²+1+k=0

f(1)=2+9+1+k=0

k=-(2+9+1)=-12

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