find the valu of k for which x^2-(k+1)x+4=0has equal roots
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Answered by
1
let the roots are a, a
a + a = k+1
2a = k+1
a*a = 4/1 , a^2 = 4 ,
a = +-2
2*2 = k+1
k = 3
2*(-2) = k+1
k = -5
a + a = k+1
2a = k+1
a*a = 4/1 , a^2 = 4 ,
a = +-2
2*2 = k+1
k = 3
2*(-2) = k+1
k = -5
divyagupta2:
I have find two values of k and u only 1 ..so think it's wanna be long
Answered by
6
hii dear ..
hope it helps u..!!
hope it helps u..!!
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