Question

find the valu of k , if x-1 is a factor of p(x)=2xsquare+kx+rute2

Answer 1

I don't know sorry am very sorry

In ,

Answer 2

Step-by-step explanation:

x-1=0

x=1

put x=1 in our main eqn

p(1)=2x²+kx+√2

p(1)=2*1²+k*1+√2

p(1)=2+k+√2

2+k+√2=0

k= -(2 + √2)