Question

find the valu of k so that the following systems of equations has no solution 3×-y-5=0,6-2y+k=0​

Answer 1

Answer:

The value of k = 10.

Step-by-step explanation:

Given two equations, 3x – y – 5 = 0 (i.e) 3x - y = 5 …. (1)

6x - 2y – k = 0 (i.e) 6x - 2y = k …. (2)

Divide equation (2) by 2, it becomes, 3x – y = (\frac{k}{2})(

2

k

) … (3)

From equation (1) and (3) LHS are equal, hence consider RHS

(\frac{k}{2})(

2

k

) = 5, k = 10 for the problem to have solution,

Condition for no solution be k ≠ 10.

Answer 2

Step-by-step explanation:

See the above attachment.

Hope it will help you.

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