Question

Find the valu of x,(-7/8)^2+x=[(-7/8)^2/3÷(-7/8)^-1/3]​

Answer 1

Answer:

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Answer 2

Find the value of X:

Step-by-step explanation:

$\ Given \ value:$

$(-\frac{7}{8})^{2}+x=[(-\frac{7}{8})^{\frac{2}{3}}\div(-\frac{7}{8})^{-\frac{1}{3}}]\\\\\therefore \frac{a^{n}}{a^{m}}=a^{n-m}\\\\\because \frac{(-\frac{7}{8})^{\frac{2}{3}}}{(-\frac{7}{8})^{-\frac{1}{3}}}\\\\\rightarrow (-\frac{7}{8})^{\frac{2}{3}-(-\frac{1}{3})}\\\\\rightarrow (-\frac{7}{8})^{(\frac{2}{3}+\frac{1}{3})}\\\\\rightarrow (-\frac{7}{8})^{(\frac{2+1}{3})}\\\\\rightarrow (-\frac{7}{8})^{(\frac{3}{3})}\\\\\rightarrow (-\frac{7}{8})^{1}\\\\\rightarrow (-\frac{7}{8})$

$\ Solution:$

$\rightarrow (-\frac{7}{8})^{2}+x=[-\frac{7}{8}]\\\\\rightarrow (\frac{49}{64})+x=[-\frac{7}{8}]\\\\\rightarrow x=[-\frac{7}{8}-\frac{49}{64}]\\\\\rightarrow x=-[\frac{7}{8}+\frac{49}{64}]\\\\\rightarrow x=-[\frac{56+49}{64}]\\\\\rightarrow x=-\frac{105}{64} \ or \ 1.640$

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