Math, asked by vidhyasamyuktha0410, 2 months ago

find the valu of x so that
(i) [5/3}^-2*[5/3]^-14= [5/3]^8x
(ii) (-2)^3*(-2)^-6=(-2)^2x-1
(iii) (2^-1+4^-1+6^-1+8^-1)x=1

Answers

Answered by Leonjr549
0

Answer:

find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}^-2*[5/3]^-14= [5/3]^8x (ii) (-2)^3*(-2)^-6=(-2)^2x-1 (iii) (2^-1+4^-1+6^-1+8^-1)x=1find the valu of x so that (i) [5/3}

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