Question

find the value 0f discrminant for the quadratic equation 2x²+x+1=0​

Answer 1

Answer:

-7

Step-by-step explanation:

Hope its clear

Answer 2

EXPLANATION.

$\sf \: quadratic \: equation \: = 2 {x}^{2} + x + 1 = 0$

As we know that,

$\sf \: discriminant \: = d \: = {b}^{2} - 4ac$

Put the value in equation, we get.

$\sf \: (1) {}^{2} - 4(2)(1) = 0$

$\sf \: 1 - 8 = 0$

$\sf \: - 7 = 0$

As we can see, that,

D < 0 it means Roots is imaginary.

$\sf \: \underline{more \: information}$

$\sf \: (1) = d \: >0 \: \: or \: {b}^{2} - 4ac \: > 0 \\ \sf \: roots \: are \: real \: and \: \: unequal$

$\sf \: (2) = d = 0 \: or \: b {}^{2} - 4ac \: = 0 \\ \sf \: roots \: are \: real \: and \: equal$

$\sf \: (3) = d < 0 \: or \: {b}^{2} - 4ac \: < 0 \\ \sf \: roots \: are \: imaginary$