Question

Find the value 1) 32-2x²+y. [when x=1 , y= -1]
2) 32-2x²+y [when x=-2, y=-3]​

Answer 1

Step-by-step explanation:

Find the value 1) 32-2x²+y. [when x=1 , y= -1]

2) 32-2x²+y [when x=-2, y=-3]

Answer 2

Answer:

1.=32-2.1.1+(-1)

=32-2-1

=32-3

=29

Step-by-step explanation:

=32-2.(-2).(-2)+(-3)

=32-2(4)-3

=32-8-3

=32-11

=21