Find the value: 1/4[2925^2- 2927 x 2923)
Answers
Answered by
0
Answer:
Step-by-step explanation:
given 1/4(2925^2-2927*2923) find the value
if the number (2925^2-2927*2923)is multiplying by denoinator then
the value is 1/4(8555625-8555621)
1/4(4)=1/16
0.0625
if the number is multypling by numenaror then
1(4)/4
=1
Answered by
2
Answer:
=1
Step-by-step explanation:
=1/4[2925^2-{(2925+2)*(2925-2)}] Rule: a^2-b^2=(a+b)(a-b) Here,a=2925,b=2
=1/4[2925^2-{(2925)^2-(2)^2}]
=1/4[2925^2-2925^2+2^2] :2925^2-2925^2 cancels each other.
=1/4[2^2]
=1/4*4
=1
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