find the value(-1)^n+(-1)^2n+(-1)^2n+1+(-1)^4n+2 where n is any positive odd integer
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1
bases are same so only powers can be calculated .I guess
saumyasuksham:
No....
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Answer:
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Step-by-step explanation:
Given that n is a positive odd integer
⇒ 2n and 4n + 2 are even positive integers and n and 2n + 1 are odd positive
integers.
∴ (–1)n
= – 1, (–1)2n
= + 1, (–1)2n + 1 = – 1, (–1)2n + 2 = + 1
∴ (–1)n
+ (–1)2n
+ (–1)2n + 1 + (–1)4n + 2 = – 1 + 1 – 1 + 1 = 0
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