Question

Find the value (2^-1 - 4^-1)^2

answer with explanation to be brainless as fast as possible pls

Answer 1

Answer:

$\dfrac{1}{16}$

Step-by-step explanation:

Given,

$(2^{-1} - 4^{-1})^2\\\\=\left(\dfrac{1}{2}- \dfrac{1}{4}\right)^2\\\\=\left(\dfrac{2-1}{4}\right)^2\\\\=\left(\dfrac{1}{4}\right)^2\\\\= \dfrac{1}{16}$