find the value, (2/5 a2b) * (-15 b2ac) * (- 1/2 c2), if a = 1, b = 2, and c = 3
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Formula,
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
⇒(a+b+c)
2
=a
2
+b
2
+c
2
+2(ab+bc+ca)
Given,
ab+bc+ca=10,a
2
+b
2
+c
2
=16
⇒(a+b+c)
2
=16+2(10)
a+b+c=
16+20
=6
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