Question

find the value (-2/7)^-4*(-2/7)^-2
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Answer 1

(-2/7)^-4*(-2/7)^-2

by using [(a)^m*(a)^n=(a)^m+n]

=(-2/7)^(-4)+(-2)

=(-2/7)^-6

=(7/-2)^6

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Answer 2

Answer:

here it is

Step-by-step explanation:

= - (2/7)^ - 4 × ( - 2/7)^ - 2

Now if the bases are same then the powers get added up

so,

= ( - 2/7)^ - 4 + ( - 2)

= ( - 2/7)^ -6