Question

Find the value (3^0+4^-1)×2^2

Answer 1

Given Question is (3^0 + 4^-1) * 2^2

We know that a^0 = 1.

= > 2^2(1 + 1/4)

= > 4(1 + 1/4)

= > 4(5/4)

= > 5.


Therefore the value = 5.


Hope this helps!

Answer 2

Hey there,

Your answer.

$= > (3 {}^{0} + 4 {}^{ - 1} ) \times 2 {}^{2} \\ \\ = >( 1 + \frac{1}{4} ) \times 4 \\ \\ = > ( \frac{4 + 1}{4} ) \times 4 \\ \\ = > \frac{5}{4} \times 4 \\ \\ = > cut \: 4 \: by \: 4 \\ \\ = > 5$


:-) Hope it helps !