Math, asked by tleipuii, 5 months ago

find the value :(3√3-2√3) (3√3+2√2)​

Answers

Answered by chinni08
2

answer:

explaination:

  • 9+2√6 is answer.
Attachments:
Answered by navdeepmalik1254
1

Answer:

3+2(2)^1/2]^-3+[3-2(2)^1/2]^-3

=1/[3+2(2)^1/2]^3+1/[3-2(2)^1/2]^3

=[{3-2(2)^1/2}^3+{3+2(2)^1/2}^3]÷[{3+2(2)^1/2}^3×{3-2(2)^1/2}^3

=[{3-2(2)^1/2+3+2(2)^1/2}^3-3×{3-2(2)^1/2}{3+2(2)^1/2}{3-2(2)^1/2+3+2(2)^1/2}]÷[3^2–{2(2)^1/2}^2]

=[6^3-3(9-8)(6)]÷[9-8]

=216-18

=198

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