find the value :(3√3-2√3) (3√3+2√2)
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answer:
explaination:
- 9+2√6 is answer.
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Answer:
3+2(2)^1/2]^-3+[3-2(2)^1/2]^-3
=1/[3+2(2)^1/2]^3+1/[3-2(2)^1/2]^3
=[{3-2(2)^1/2}^3+{3+2(2)^1/2}^3]÷[{3+2(2)^1/2}^3×{3-2(2)^1/2}^3
=[{3-2(2)^1/2+3+2(2)^1/2}^3-3×{3-2(2)^1/2}{3+2(2)^1/2}{3-2(2)^1/2+3+2(2)^1/2}]÷[3^2–{2(2)^1/2}^2]
=[6^3-3(9-8)(6)]÷[9-8]
=216-18
=198
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