Find the value: (3^X × 9^X+1) ÷ (3^X-1 x 9^X+1)
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Answer:
3
Step-by-step explanation:
Given, (3^X × 9^X+1) ÷ (3^X-1 x 9^X+1)
[3^X × (3²)^X+1] ÷ [3^X-1 x(3²)^X+1]
[3^X × 3^(2X+2)] ÷ [3^(X-1) x3^(2X+2)]
[3^(X+2X+2)] ÷ [3^(X-1 +2X+2)]
3^[(X+2X+2)-(X-1 +2X+2)]
3^[X+2X+2-X+1 -2X-2]
3^[X+2X+2-X+1 -2X-2]
3^1
3
Used some properties of exponents.
This is the required answer.
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