Question

find the value 3ycube-4y+√11 when y=2​

Answer 1

Answer:

When y=2

3y³ - 4y + √11 = 3(2)³ - 4(2) + √11

= 3x8 - 4x2 + √11

=24 - 8 + √11

=16 + √11

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Answer 2

We have been asked to find the value of:

$\longrightarrow{\tt{{(3y)}^{3} - 4y + \sqrt{11}}}$

We have already been told the value of y.

So we just have to substitute the value of y in the polynomial to find it's value.

The process will be :

$\longrightarrow{\tt{p(y) = {(3y)}^{3} - 4y + \sqrt{11}}}$

$\longrightarrow{\tt{p(2) = {3(2)}^{3} - 4(2) + \sqrt{11}}}$

$\longrightarrow{\tt{p(2) = 3 \times 8 - 8 + \sqrt{11}}}$

$\longrightarrow{\tt{p(2) = 24 - 8 + \sqrt{11}}}$

$\longrightarrow{\tt{p(2) = 16 + \sqrt{11}}}$

So the value of the given polynomial is :

$\large{\boxed{\implies{\tt{16 + \sqrt{11}}}}}$

Steps followed :

• Firstly we have put up the values of y in the given polynomial.
• Then we have simplified the cube and square terms.
• Then finally did operations like Addition , Subtraction and Multiplication with the same.
• Finally got the value .