Question

find the value???????

Answer 1

$= > \sqrt{5 + 2 \sqrt{6} } \\ \\ \\ = > \sqrt{3 + 2 + 2 \sqrt{6} } \\ \\ \\ = > \sqrt{ {( \sqrt{3})}^{2} + {( \sqrt{2} )}^{2} +2( \sqrt{3} \times \sqrt{2} )} \\ \\ \\ = > \sqrt{ ( \sqrt{3} + {\sqrt{2})}^{2} } \\ \\ \\ = > ( \sqrt{3} + \sqrt{2} ) {}^{2 \times \frac{1}{2} } \\ \\ \\ = > \sqrt{3} + \sqrt{2}$