Question

find the value ( 64 a² ÷ 112ab + 49b² ) a = 1/2 , b = 3/2
please solve​

Answer 1

Answer:

169/4.

Step-by-step explanation:

$64 {a}^{2} - 112ab + 49 {b}^{2} = {(8a)}^{2} - 2(8a)(7b) + {(7b)}^{2} \\ \\ = {(8a - 7b)}^{2} \\ \\ = {(8 \times \frac{1}{2} - 7 \times \frac{3}{2} )}^{2} \\ \\ = \frac{{(8 - 21)}^{2} }{ {2}^{2} } \\ \\ = {( \frac{13}{2} )}^{2} \\ \\ = \frac{169}{4} .$