Question

Find the value
7p - 2 = 14
​

Answer 1

Answer:

Given Eqn is (2p+1)x 2 − b(7p+2)x + c7p−3 =02

If this eqn has equal roots DiscriminantD=0b 2 −4ac=0⇒(7p+2) 2 −4(2p+1)(7p−3)=0⇒49p 2 +4+28p−4(149 2 −6p−3+7p)=0⇒49p 2 +4+28p−(56p 2 −24p−12+28p)=0⇒49p 2 +4+28p−56p 2 −4p+12=0⇒−7p 2 +24p+16=0⇒7p 2 −24p−16=0⇒P=4, 7−4

Now Roots At

i)P=4 ii)P=7−4Eqn is 9x 2

−30x+25=0 Eqn is7−1 x 2 +2x−7=03x−5=0 x2−14x+49=0x= 35 x=7

Answer 2

7p - 2 = 14

=> 7p = 14 + 2

=> 7p = 16

=> p = 16/7