Question

Find the value 8⅔.2⅞ / 4²

Answer 1

Answer:

PLEASE MAKE ME THE BRILLIANT

Answer 2

Answer:

The value is $0.4585$ or $2^{\frac{-9}{8} }$.

Step-by-step explanation:

Given number is $\frac{8^{\frac{2}{3}}.2^{\frac{7}{8}}}{4^{2} }$.

We need to simplify the number.

We can write $8$ as $2^3$.

Now substitute in the number,

$\frac{2^{3\times\frac{2}{3}}.2^{\frac{7}{8}}}{4^{2} }$

We can see that both the $3$s cancel each other.

$\frac{2^{2}.2^{\frac{7}{8}}}{4^{2}}$

Now we can write $4$ as $2^2$.

$\frac{{{2^2}}.2^{\frac{7}{8}}}{2^{2\times 2}}$

We know the formula $x^a.x^b=x^{a+b}$.

Applying the formula in the above step,

$\frac{2^{2+\frac{7}{8}}}{2^{2\times2}}$

$\frac{2^{\frac{23}{8}}}{2^{4}}$

We know the formula $\frac{x^a}{x^b}=x^{a-b}$.

Applying the formula in the above step,

$2^{\frac{23}{8}-4}$

$2^{\frac{-9}{8} }$

$0.4585$

Therefore, the value of $\frac{8^{\frac{2}{3}}.2^{\frac{7}{8}}}{4^{2} }$ is $0.4585$ or $2^{\frac{-9}{8} }$.