Question

find the value a and b
7-4√3/7+4√3=a+b√3

Answer 1

Step-by-step explanation:

answer is that question by a. u. abhi

Answer 2

$LHS = \frac{(7-4\sqrt{3})}{(7+4\sqrt{3})} \\= \frac{(7-4\sqrt{3})(7-4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3})} \\= \frac{(7-4\sqrt{3})^{2}}{7^{2} - (4\sqrt{3})^{2}} \\= \frac{ 7^{2} + (4\sqrt{3})^{2} - 2 \times 7 \times 4\sqrt{3}}{49 - 48 }\\= 49+48-56\sqrt{3}\\= 97 - 56\sqrt{3} \\= 97 + (-56)\sqrt{3} \: --(1)$

$RHS = a + b\sqrt{3} \: ---(2)$

/* Compare (1) and (2) , we get */

$a = 97 , \: b = -56$

Therefore.,

$\green { a = 97 , \: b = -56}$

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