find the value 'a' if'x-1' is the factor of a²x³-4ax+4a-1
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due to x-1 is a factor of f(X) by the factor theorem ,I have done this
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Hello Dear!!!
Here's your answer....
The given expression is
a²x³-4ax+4a-1
Zero of x-1 is
x-1 = 0
x = 1
a²(1)³ -4a(1) + 4a -1
a² -4a+4a-1
a²-1
a² - 1²
It is in the form of a² - b²
It is equal to (a+b)(a-b)
(a+1)(a-1) = 0
a+1 = 0 and a-1 = 0
a = -1 and a = 1
The value of a is -1 or 1
______________________________________
HOPE THIS HELPS YOU....
Here's your answer....
The given expression is
a²x³-4ax+4a-1
Zero of x-1 is
x-1 = 0
x = 1
a²(1)³ -4a(1) + 4a -1
a² -4a+4a-1
a²-1
a² - 1²
It is in the form of a² - b²
It is equal to (a+b)(a-b)
(a+1)(a-1) = 0
a+1 = 0 and a-1 = 0
a = -1 and a = 1
The value of a is -1 or 1
______________________________________
HOPE THIS HELPS YOU....
Anonymous:
Hey Harshu , what are u using ??
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