find the value a of ((10)^-2)^a=1
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Answered by
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(10^-2)^a=10^0
10^-2a = 10^0
as base are equal exponents are equal
-2a = 0
-a =0/2
a =0
hope this helps
10^-2a = 10^0
as base are equal exponents are equal
-2a = 0
-a =0/2
a =0
hope this helps
depudhivya1:
sir antha question ((10)^-2)^a= 1.....then how is come from ((10)^-2)^a= 10^0...pls sir..i didn't understood..pls explain me sir
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