Question

Find the value a³-3a²b+3ab²-b³when a=2,b=-1

Answer 1

Answer:

Answer is 27

Step-by-step explanation:

We know ,a^3-b^3-3a^2b+3ab^2= (a-b)^3

If a=2

b = -1

Then,

(a-b)^3= {2-(-1)}^3

= (2+1)^3

= 3^3

= 27

Answer 2

Answer:

answer is 27

We know, a^3-b^3-3a^2b+3ab^2=(a-b) ^3

If a=2

b=1

Then,

(a-b)^3=[2-(-1)]^3

=(2+1)^3

=3^3

=27

hope you got help by this answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!