Question

Find the value
and I are zeroes of the polynomial p(x) = 2x2 – 3x + 1 or not? Justify
Whether​

Answer 1

Step-by-step explanation:

Step - by - step explanation :

here , the quadratic polynomial is 2x2-3x + 1 .

we have to chech whether 1/2 and1 are zeroees of this polynomial.

okk

X - 1 / 2 = 0

x = + 1 / 2

. so , substitute the value of x in the above quadratic polynomial ..

then we get :

2 ( 1/2 ) 2 -3 ( 1/2 ) + 1 = 0

after opening the brackets we get .. 1/2 - 3/2 +1 = O

.. LCM = 2

So , ( 1-3 + 2 ) / 2

= 0 ( -2 + 2 ) / 2

= 0

0 / 2 = 0

O = 0

therefore ,

it is a zero of the polynomial ..

nxt we should chech 1 is a zero or not so

X + 1 = 0

X = -1

substitute the value of x in the polynomial given in the question then we get :

2 ( -1x - 1 ) - 3 ( -1 ) + 1

0= 2 + 3 + 1

0= 5 + 1

0= 6 is not equal to o .

so 1 is not zero of this polynomial .

Answer 2

Answer: Your answer is here:-

Step-by-step explanation: If, X= 1

So, P(1)= 2x2-3x1+1=0

               4-3+1=0

               1+1=0

               2 is not equal to 0

If we put value 1 in the x so we get 2 instead of 0, and in zeros of polynomial L.H.S=R.H.S. But in this case L.H.S is not equal to R.H.S. So, we have to do trail and error method to get the exact value of x from which we get L.H.S=R.H.S. :- So, this your justification.

So, here if we put value of x as 5/3 so we it will become zeros of polynomial.

P(5/3)= 2x2-3x5/3+1=0

            4-5+1=0

            -1+1=0

            0=0

So, this is the correct answer of this question.

If in this we put 5/3 instead of 1 in the value of x we get L.H.S=R.H.S

Hope it helpful to you.

Thanks.