Question

find the value
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Answer 1

$⇝(2x+ \frac{ 1 }{ 2 } )( \frac{ 3x }{ 2 } - \frac{ 1 }{ 4 } ) \\⇝\left(2x+\frac{1}{2}\right)\left(\frac{2\times 3x}{4}-\frac{1}{4}\right) \\⇝ \left(2x+\frac{1}{2}\right)\times \left(\frac{2\times 3x-1}{4}\right) \\⇝\left(2x+\frac{1}{2}\right)\times \left(\frac{6x-1}{4}\right) 2x\times \left(\frac{6x-1}{4}\right)+\frac{1}{2}\times \left(\frac{6x-1}{4}\right) \\⇝ \frac{6x-1}{2}x+\frac{1}{2}\times \left(\frac{6x-1}{4}\right) \frac{6x-1}{2}x+\frac{6x-1}{2\times 4} \\ ⇝\frac{\left(6x-1\right)x}{2}+\frac{6x-1}{2\times 4} \\ ⇝\frac{\left(6x-1\right)x}{2}+\frac{6x-1}{8} \\ \frac{4\left(6x-1\right)x}{8}+\frac{6x-1}{8} \\⇝ \frac{4\left(6x-1\right)x+6x-1}{8}\\⇝\frac{24x^{2}-4x+6x-1}{8} \\⇝ \frac{2x-1+24x^{2}}{8}$

$\huge \ \mathfrak{@DarkShadow7083 }$