Question

find the value discrminant is of the equation x^2+7x+12=0
please fast answer​

Answer 1

Answer:

1

Step-by-step explanation:

x^2+7x+12=0 ; ax^2+bx+c=0

D=b^2 -4ac

=7×7 -4×1×12

=49-48

=1

Answer 2

Answer:

in x^2+7x+12=0

a=1, b=7 and c=12

now (-b±$\sqrt{b^2-4ac}$)/2a

[-7±root(49-4*1*12)]/2

(-7+or-root(49-48))/2

(-7+or-root(1))/2

[-7+1]/2 or [-7-1]/2

therefore  x=-3 , -4