find the value for 3x+4y=18,4x+3y=17 sum
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Answer:
Step-by-step explanation:
The given equations are
3x+4y=18 ...(i)
4x+3y=17 ...(ii)
On multiplying (i) by 4 and (ii) by 3 and subtracting, we get
12x+16y=72
−
1
2x
−
+
9y=
−
5
1
7y=21
⇒y=3
On putting y=3 in (i), we get
3x+12=18⇒3x=6⇒x=2
∴x=2,y=3
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