Question

find the value for k for which the system of equations 8x+5y=9 ,kx+10y=15 has no solution

Answer 1

heya

here is ur answer

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given :-

8x + 5y = 9

kx + 10y = 15

✴ they have no solution ( given)

so they are parallel lines

$\frac{a1}{a2} = \frac{b1}{b2} \: \: is \: not \: equal \: to \: \: \frac{c1}{c2}$

➡ 8/k = 5/10 ≠ -9/-15

➡8/k = 5/10

➡8/k = 1/2

➡k = 8*2

➡k.= 16

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hope it helps u..!!

thnkq

Answer 2

Heya....!!!

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Given :

8x + 5y = 9

kx + 10y = 15

Transposing to RHS

8x+5y-9=0

kx+10y-15=0

Given that they have NO solution

Hence, 
a1/a2 = b1/b2 not equal to c1/c2

$a_{1}/a_{2} = b_{1} / b_{2} \neq c_{1}/c_{2}$

a1 = 8
a2 = k

b1 = 5
b2 = 10

c1 = 9
c2 = 15


$a_{1}/a_{2} = b_{1} / b_{2} \neq c_{1}/c_{2}$

8/k = 5/10 \neq 9/15

8/k = 5/10

80 = 5k

80/5 = k

16 = k

Hence,


$8_{1}/k_{2} = 5_{1} / 10_{2} \neq 9_{1}/15_{2}$

Where, 

K is 16

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Thanks....

Hope This helps....

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