find the value for m for which the roots of the equation mx [6x+10]+25=0, are equal.
Answers
Answered by
183
mx(6x + 10) + 25 = 0
6mx² + 10mx + 25 = 0
as roots are equal
therefore discriminant = 0
b² - 4ac = 0
100m² - 4(6m)(25) = 0
m² = 6m
m = 6
6mx² + 10mx + 25 = 0
as roots are equal
therefore discriminant = 0
b² - 4ac = 0
100m² - 4(6m)(25) = 0
m² = 6m
m = 6
Answered by
43
mx(6x+10)+45=0
6m^+10m+25=0
applying b^- 4ac=0
(10m)^-4×6m×25=0
100m^-600m=0
m^-600/100m=0
m^-6m=0
m(m-6)=0
m=0,m-6=0
m=0
m=6
6m^+10m+25=0
applying b^- 4ac=0
(10m)^-4×6m×25=0
100m^-600m=0
m^-600/100m=0
m^-6m=0
m(m-6)=0
m=0,m-6=0
m=0
m=6
Similar questions