Find the value for m if the line 5x plus 3y =10 and 2x-my =6 are parallel
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5x+3y=10
3y=10-5x
y=(-5/3)x+(-10/3)
is of the form y=mx+c
therefore m1=(-5/3)
it is a parallel line hence, m1=m2=(-5/3)
3y=10-5x
y=(-5/3)x+(-10/3)
is of the form y=mx+c
therefore m1=(-5/3)
it is a parallel line hence, m1=m2=(-5/3)
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