find the value for p, if the mean of the following distribution is 18
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Answer:
p = 1.
Step-by-step explanation:
Mean = ∑xf / ∑f
= (13*8 + 15*2 + 17*3 + 19*4 + (20 + p)5p + 23*6) / (8+2+3+4+5p+6)
= (5p^2 + 100p + 399) / (5p + 23) = 18
5p^2 + 100p + 399 = 18(5p + 23)
5p^2 + 100p + 399 = 90p + 414
5p^2 + 10p - 15 = 0
p^2 + 2p - 3 = 0
(p + 3)(p - 1) = 0
p = 1 ( as p cannot be negative - we cannot have a frequency of 5*-3)
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