Math, asked by hinivijayaljhj, 1 year ago

Find the value for which the system of equation 3x +5y =0 , kx +10y = 0 has non zero solution

Answers

Answered by Anonymous
291
 condition for the system of equations to have non-zero solutions,
a1/a2 = b1/b2 = c1/c2
here, a1 = 3 , a2 = k, b1 = 5 , b2 = 10
3/k = 5/10
3/k = 1/2
k = 6
Answered by mysticd
84

Answer:

For all real values k other than 6 , the system of equations has non zero solution.

Step-by-step explanation:

Given system of equations:

3x+5y=0 ,

kx+10=0 ,

Compare this with a1x+b1y+c1=0

and

a2x+b2y+c2 = 0, we get

a1 = 3 , b1 = 5, c1 = 0

a2 = k , b2= 10, c2=0

The equations have non zero solution,

Here ,

a1b2-a2b1≠0

=> 3×10-k×5 0

=> 30 - 5k 0

=> -5k -30

On dividing each term by -5, we get

=> k 6

If plot the lines ,we will notice that they are parallel.

So, for this problem to have non -zero solution , k is any real number other than 6.

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