Math, asked by princeyadav26, 1 year ago

find the value how to finding value​

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Answered by Anonymous
4
ʜᴇʏᴀ ᴍᴀᴛᴇ ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ 
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●We know that :-

 {sin}^{2}  \alpha  =  \sqrt{1 -  {cos}^{2}  \alpha }
 \:  \:  \:  \:  =  \sqrt{1 -  \frac{1}{2} }
 \:  \:  \:  =  \sqrt{ \frac{1}{2} }
 \:  \:  \:   =  \frac{1}{ \sqrt{2} }
 {sin}^{2}  \alpha  =  \frac{1}{ \sqrt{2} }

princeyadav26: pr iska ans only 1/2 aa reha he
Answered by codiepienagoya
1

Finding the value:

Step-by-step explanation:

\ Given \ that:\\\\cos^2 \theta =\frac{1}{2}\\\\\ Find: \\\\sin^2 \theta = ?\\\\\therefore \  \ sin^2 \theta + cos^2 \theta \ = \ 1\\\\\ Solve: \\\\\rightarrow sin^2 \theta + \frac{1}{2} \ = 1\\\\\rightarrow sin^2 \theta =1\ - \frac{1}{2} \\\\\rightarrow sin^2 \theta = \frac{2-1}{2} \\\\\rightarrow sin^2 \theta = \frac{1}{2} \\\\\because   sin^2 \theta = \frac{1}{2} \\\\

Learn more:

  • Simplify: https://brainly.in/question/15387636
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