Find the value (i) SinA.SinB- CosA.CosB ,when A+B =pi
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Answer:A+B=½π
A=½π-B
sinA=sin(½π-B)=cosB
B=½π-A
sinB=sin(½π-A)=cosA
∴LHS
=sinA+cosA+(cosA)-(sinA)
=0
Step-by-step explanation:
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Answer:
Find the value (i) SinA.SinB- CosA.CosB ,when A+B =pi
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