Question

find the value if
$\sqrt{5} = 2.236$

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{3 + \sqrt{5} }{3 - \sqrt{5} } \\ \\ on \: rationalizing \: the \: denominator \: we \: get \\ \\ \\ \\ = \frac{3 + \sqrt{5} }{3 - \sqrt{5} } \times \frac{3 + \sqrt{5} }{3 + \sqrt{5} } \\ \\ using \: the \: identities \\ {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ = \frac{ {(3)}^{2} + {( \sqrt{5} )}^{2} + 2 \times 3 \times \sqrt{5} }{{(3)}^{2} - {( \sqrt{5} )}^{2} } \\ \\ = \frac{9 + 5 - 6 \sqrt{5} }{9 - 5} \\ \\ = \frac{14 - 6 \sqrt{5} }{4} \\ \\ = \frac{7 - 3 \sqrt{5} }{2} \\ \\ = \frac{7 - 3 \times 2.236}{2} \\ \\ = \frac{7 - 6.708}{2} \\ \\ = \frac{0.292}{2} \\ \\ = 0.146$


Hope this helps!!!!

@Mahak24

Thanks...
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