find the value if unknown x in the following diagram
Attachments:
Answers
Answered by
0
Step-by-step explanation:
In ∆ABC
A+B+C=180{Angle sum property of triangle}
x+50+60=180
x+110=180
x=180-110
x=70
In∆PRQ
P+R+Q=180
90+x+30=180
x+120=180
x=180-120
x=60
Answered by
1
Answer:
In triangle ABC,
<A + <B + <C = 180° [Angle sum property]
x + 50° + 60° = 180°
x + 110° = 180°
x = 180° - 110°
x = 70°
In triangle QPR,
<P + <Q + <R = 180°
90° + 30° + x = 180°
120° + x = 180°
x = 180° - 120°
x= 60°
Similar questions