Find the value if x=2,A=-1,B=-3 4a2(square)-b2(square)+6a2(square)-7b2(square)
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Answered by
6
X = 2
A = -1
B = -3
4a²-b²+6a²-7b²
Putting the Value
4×-1²-(-3)²+6×(-1)²-7(-3)²
=4×1-9+6-7×9
=4-9+6-63
=72+10
=82 Ans
A = -1
B = -3
4a²-b²+6a²-7b²
Putting the Value
4×-1²-(-3)²+6×(-1)²-7(-3)²
=4×1-9+6-7×9
=4-9+6-63
=72+10
=82 Ans
Amankhan993653:
check your question or
send me the screenshot of question
ya I know that's for the other question
there were 2 sums in the text
try to solve the other one please
send us the question
I put if
I put it **
can't check it
kk
Answered by
1
my name is nitesh and what is your name
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