Question

find the value if: x=3,y=-2,z=5:3x^2-4y^2+5z^2​

Answer 1

Answer:

when x=3 y= -2 z= 5 , then,

3x^2-4y^2+5z^2

= 3 × (3)^2-4×(-2)^2+5 ×(5)^2

= 3×9-4×4+5×25

=27-16+125

=27+125-16

= 152-16

= 136.

Answer 2

Here is Your answer....❤

when x = 3 y =- 2 z = 5 ,then

$3 {x}^{2} - 4 {y}^{2} + 2 {z}^{2}$

$= 3 \times {(3)}^{2} - 4 \times {( - 2)}^{2} + 5 \times {(5)}^{2}$

$= 3 \times 9 - 4 \times 4 + 5 \times 25$

$= 27 - 16 + 125$

$= 27 + 125 - 16$

$= 152 - 16$

$= 136$

Hope it helps...

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