Question

find the value if x such that x,x,x+3,x+9are first 3 terms of a
GP

Answer 1

Answer:

3

Step-by-step explanation:

a=x

r=(x+3)/x

r=(x+9)/(x+3)

(x+3)/x=(x+9)/(x+3)

(x+3)²=x(x+9)

x²+9+6x=x²+9x

3x=9

x=3