find the value if x such that x,x,x+3,x+9are first 3 terms of a
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Answer:
3
Step-by-step explanation:
a=x
r=(x+3)/x
r=(x+9)/(x+3)
(x+3)/x=(x+9)/(x+3)
(x+3)²=x(x+9)
x²+9+6x=x²+9x
3x=9
x=3
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