find the value ( in the image the value of _____________is equal to
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Hi ,
1 ) 1/(√2+1 )
= (√2-1)/[(√2+1)(√2-1)]
= (√2-1)/[(√2)²-1²]
= √2 - 1
Similarly ,
We get all the values ,
Now ,
1/( √2+1 ) + 1/(√2+√3)+....+1/(√8+√9)
= √2-1+√3-√2+√4-√3+..+√9-√8
= -1 + √9
= -1 + 3
= 2
Option ( C ) is correct.
I hope this helps you.
: )
1 ) 1/(√2+1 )
= (√2-1)/[(√2+1)(√2-1)]
= (√2-1)/[(√2)²-1²]
= √2 - 1
Similarly ,
We get all the values ,
Now ,
1/( √2+1 ) + 1/(√2+√3)+....+1/(√8+√9)
= √2-1+√3-√2+√4-√3+..+√9-√8
= -1 + √9
= -1 + 3
= 2
Option ( C ) is correct.
I hope this helps you.
: )
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