Question

Find the value k for the which the point (0,2) is equidistant from 2 points (3,k) (k,5)

Answer 1

given,P(0,2) is equidistant from R(3,k) and S(k,5).

∴ PR = PS

⇒PR²=PS²

(3-0)²+(k-2)²=(k-0)²+(5-2)² [using distance formula]

9+k²+4-4k=k²+9

⇒4=4k

∴k=4÷4

k=1

thus,value of k is 1

Answer 2

Answer:

given,P(0,2) is equidistant from R(3,k) and S(k,5).

∴ PR = PS

⇒PR²=PS²

(3-0)²+(k-2)²=(k-0)²+(5-2)² [using distance formula]

9+k²+4-4k=k²+9

⇒4=4k

∴k=4÷4

k=1

thus,value of k is 1

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