Question

find the value k if 2 is zero of 2x²-kx+4=0​

Answer 1

Answer:

6

Explanation:

x= 2

p ( x) = 2x²-kx+4=0​

p(2) =  2x²-kx+4=0​

           = 2 x 2² - 2k +4 = 0

             = 8 - 2k +4 = 0

            = 12 - 2k = 0

             = -2k = -12

             = k =-12/-2

              = k = 6

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Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

find the value k if 2 is zero of 2x²-k+4=0

ANSWER:-

Given:-2 is zero of 2x^2-kx+4=0

now:-

Put 2 instead of x to find the value of k:-

$➩2 {x}^{2} - k(2) + 4 = 0$

$➩2{(2)}^{2} - 2k + 4 = 0$

$➩8 - 2k + 4 = 0$

$➩ - 2k = - 4 - 8$

$➩ - 2k = - 12$

$➩k = 6 \: answer$

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