Question

find the value k if x=1, y=6 is a solution of the 8x-ky+k^2=0​

Answer 1

Answer:

k=2 k=4

Step-by-step explanation:

substitute the values in eqn

8(1)-k(6)+k^2=0

k^2-6k+8=0

k^2-2k-4k+8=0

k(k-2)-4(k-2)=0

(k-2)(k-4)=0

k=2 k=4